Hi I'm running vserver 2.0 and I've attempted to create a new "127.0.0.1" loopback "lo" interface for my guest. I've read that packets for this interface should be redirected by the kernel to the guest's other default interface, rather than going through the host's "127.0.0.1", and that's very acceptable to me. However I suspect that what I've created is instead a "127.0.0.1" interface for the guest that is the exact same "127.0.0.1" interface for the host, ie the host and guest are now sharing the one loopback interface, which is what I don't want. I suspect this because when I run the "ip addr ls" command from the guest, I get output which says the "lo" interface's scope is "host", eg # ip addr ls 1: lo: <LOOPBACK,UP,10000> mtu 16436 qdisc noqueue link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 brd 127.255.255.255 scope host lo 2: eth0: <BROADCAST,MULTICAST,UP,10000> mtu 1500 qdisc pfifo_fast qlen 1000 link/ether 00:60:b0:ce:75:4e brd ff:ff:ff:ff:ff:ff inet 192.168.1.132/24 brd 192.168.1.255 scope global secondary eth0 Have I created the loopback interface incorrectly as I suspect ? If I have, can you please tell me how I should have created the guest's loopback interface ? My host is running Debian Etch with the default vserver (ie v2.0.2.2). I've created the guest's "127.0.0.1" loopback interface by moving the guest's existing "eth0" interface directory (ie "/etc/vservers/<guest>/interfaces/0") to "/etc/vservers/<guest>/interfaces/1", then creating a new "/etc/vservers/<guest>/interfaces/0" directory, and under it creating the "dev", "ip" and "prefix" files with the following contents: dev: lo ip: 127.0.0.1 prefix: 8 Many thanks, Declan